4x^2-89=2027

Solution for 4x^2-89=2027 equation:

4x^2-89=2027

We move all terms to the left:

4x^2-89-(2027)=0

We add all the numbers together, and all the variables

4x^2-2116=0

a = 4; b = 0; c = -2116;
Δ = b2-4ac
Δ = 02-4·4·(-2116)
Δ = 33856
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{33856}=184$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-184}{2*4}=\frac{-184}{8}
=-23
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+184}{2*4}=\frac{184}{8}
=23
$